Lead sulphate precipitate. This series shows a progression as 0.5 M solution of copper sulphate (CuSO4) is added drop by drop to a test tube containing 0.2 M solution of lead (II) nitrate (Pb(NO3)2). Lead (II) sulphate precipitate (PbSO4) is formed as a result: CuSO4 + Pb(NO3)2 -> PbSO4 + Cu(NO3)2. This is an example of a double displacement reaction. | |
Licence : | Droits gérés |
Crédit: | Science Photo Library / Giphotostock |
Taille de l’image : | 6986 px × 3500 px |
Model Release : | Non requis |
Property Release : | Non requis |
Restrictions : | - |