Lead iodide precipitate, 3 of 5. This series shows a progression as lead (II) nitrate (Pb(NO3)2) is added drop by drop to a test tube containing potassium iodide (KI). Both solutions are 0.5 M concentration. Lead (II) iodide precipitate (PbI2) is formed as a result: KI + Pb(NO3)2 -> PbI2 + KNO3. This is an example of a double displacement reaction. | |
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